Odd Even Sort
R
"""
Odd even sort implementation.
https://en.wikipedia.org/wiki/Odd%E2%80%93even_sort
"""
from collections.abc import MutableSequence
from typing import Any, Protocol
class Comparable(Protocol):
def __gt__(self, other: Any, /) -> bool: ...
def odd_even_sort[T: Comparable](collection: MutableSequence[T]) -> MutableSequence[T]:
"""
Sort input with odd even sort.
This algorithm uses the same idea of bubblesort,
but by first dividing in two phase (odd and even).
Originally developed for use on parallel processors
with local interconnections.
:param collection: mutable ordered sequence of elements
:return: same collection in ascending order
Examples:
>>> odd_even_sort([5 , 4 ,3 ,2 ,1])
[1, 2, 3, 4, 5]
>>> odd_even_sort([])
[]
>>> odd_even_sort([-10 ,-1 ,10 ,2])
[-10, -1, 2, 10]
>>> odd_even_sort([1 ,2 ,3 ,4])
[1, 2, 3, 4]
>>> odd_even_sort(["c","a","b"])
['a', 'b', 'c']
>>> odd_even_sort([2.5, -1, 0.0])
[-1, 0.0, 2.5]
>>> odd_even_sort([1,"a"])
Traceback (most recent call last):
...
TypeError: '>' not supported between instances of 'int' and 'str'
"""
is_sorted = False
while is_sorted is False: # Until all the indices are traversed keep looping
is_sorted = True
for i in range(0, len(collection) - 1, 2): # iterating over all even indices
if collection[i] > collection[i + 1]:
collection[i], collection[i + 1] = collection[i + 1], collection[i]
# swapping if elements not in order
is_sorted = False
for i in range(1, len(collection) - 1, 2): # iterating over all odd indices
if collection[i] > collection[i + 1]:
collection[i], collection[i + 1] = collection[i + 1], collection[i]
# swapping if elements not in order
is_sorted = False
return collection
if __name__ == "__main__":
print("Enter list to be sorted")
input_list = [int(x) for x in input().split()]
# inputing elements of the list in one line
sorted_list = odd_even_sort(input_list)
print("The sorted list is")
print(sorted_list)